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How much work would it take to push a # 25 kg # weight up a # 20 m # plane that is at an incline of # pi / 6 #?

Answer 1

#W=2452,5J#

#theta=cancel(pi)/6*180/cancel(pi)# #theta=30^o# #sin 30=0,5# #" h:height from ground"# #h=20*sin 30^o# #h=20*0,5=10 m# #E_p=m*g*h# #"Work"=E_p=25*9,81*10# #Work=250*9,81# #W=2452,5J#
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Answer 2

To calculate the work done, you can use the formula:

Work = Force × Distance

The force required to push the weight up the incline can be found using:

Force = Weight × sin(angle)

Where: Weight = mass × gravity Gravity ≈ 9.8 m/s²

Substitute the given values:

Weight = 25 kg × 9.8 m/s² Angle = π/6 radians

Then calculate the force:

Force = 25 kg × 9.8 m/s² × sin(π/6)

Once you have the force, multiply it by the distance (20 m) to find the work done.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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