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How much work would it take to push a # 2 kg # weight up a # 4 m # plane that is at an incline of # pi / 3 #?

Answer 1

As:

#W=F.d cos theta#
where #F=mg#
#F=2*9.81#
#F=19.62N#
#W=19.62*4*cos(pi/3)#
#W=39.24J#

I hope it's useful.

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Answer 2

To calculate the work done in pushing the weight up the incline, you need to consider the force required to overcome gravity and the force required to overcome the component of gravity acting perpendicular to the incline. The total work done is the sum of the work done against gravity and the work done against the component of gravity perpendicular to the incline. Using the formula W = Fdcos(theta) for each component, where F is the force, d is the displacement, and theta is the angle between the force and displacement vectors. Then, you can calculate the total work done. Given that the weight is being pushed up the incline, the force required will be greater than the weight due to the incline. Therefore, you need to find the component of the weight parallel to the incline. The force required to overcome gravity is mg, and the force required to overcome the component of gravity perpendicular to the incline is mg*sin(theta), where m is the mass, g is the acceleration due to gravity, and theta is the angle of inclination. Substituting the given values, you can calculate the work done.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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