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How much work would it take to push a # 12 kg # weight up a # 8 m # plane that is at an incline of # pi / 3 #?

Answer 1

#W=815,56416# #"joule"#


#theta =(180/cancel(pi)).(cancel(pi)/3)#
#theta=60^o#
#cos60^o=0,866#
#h=8*0,866=6,928 meters#
#"it gains Potantial Energy when object raises to the point of B"#
#E_p=m*g*h#
#E_p=12*9,81*6,928#
#E_p=815,56416# #"joule"#
#E_p="work doing between the point A and B"#
#W=815,56416# #"joule"#

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Answer 2

To calculate the work done in pushing the weight up the inclined plane, you can use the formula: ( \text{Work} = \text{Force} \times \text{Distance} \times \text{Cosine of the angle between force and displacement} ). Given that the weight is being pushed vertically against gravity and also along the incline, the force required would be the component of the weight parallel to the incline. The force can be calculated as ( \text{Force} = \text{Weight} \times \text{sin}(\text{angle of incline}) ). Substituting the given values, you can calculate the work.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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