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How much work would it take to push a # 12 kg # weight up a # 3 m # plane that is at an incline of # pi / 3 #?

Answer 1

Work #W=F*s=407.378" "#Joules

Let #F# the force in the direction of the inclined plane at #pi/3# Given mass #m=12 " "#kg distance #d=3" "#meters Acceleration due to gravity #g=9.8 " "#m/s^2#
The weight #W#:
#W=mg=12*(9.8)=117.6" "#Newton

The operational formula

#F sin (pi/3)= W#
solving for #F#
#F=W/(sin (pi/3))=117.6/(sin(pi/3))=135.793" "#Newtons
Solve for the work #W#
#W=F*d=135.793(3)=407.378" "#Joules

May God bless you all. I hope this explanation helps.

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Answer 2

Work done = Force applied * Distance * cos(incline angle)

[ \text{{Work}} = m \times g \times d \times \cos(\text{{incline angle}}) ]

Substitute values: [ \text{{Work}} = 12 , \text{{kg}} \times 9.8 , \text{{m/s}}^2 \times 3 , \text{{m}} \times \cos\left(\frac{\pi}{3}\right) ]

Calculate the result.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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