# How much work would it take to push a # 10 kg # weight up a # 20 m # plane that is at an incline of # pi / 6 #?

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To calculate the work done, you can use the formula: ( \text{Work} = \text{Force} \times \text{Distance} \times \cos(\theta) ), where ( \theta ) is the angle of incline in radians. Given that the weight is being pushed up an incline, the force required is the component of the weight parallel to the incline, which is ( m \times g \times \sin(\theta) ). Thus, the work done would be ( \text{Work} = (m \times g \times \sin(\theta)) \times d \times \cos(\theta) ), where ( m = 10 ) kg, ( g = 9.8 ) m/s², ( d = 20 ) m, and ( \theta = \frac{\pi}{6} ). Plugging in the values, the work done would be approximately 981.5 joules.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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- How much work would it take to push a # 4 kg # weight up a # 14 m # plane that is at an incline of # pi / 4 #?
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