How much work does it take to raise a #78 kg # weight #5 m #?

Answer 1

#3800"J"#

Firstly, it should be noted that the effort expended in lifting the weight in this instance will be fully transformed into gravitational potential energy.

The gravitational potential energy of the weight when it has been raised #5 "m"# is equal to #mgh# which in this case is equal to

#3825.9 "J"#

Our final response will be given that we should have two significant digits.

#3800 "J"#

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Answer 2

Elena Albarran

Work done (W) = Force (F) × Distance (d) × cos(θ)

In this case, assuming the weight is lifted vertically:

W = m × g × d × cos(θ)

where: m = mass = 78 kg g = acceleration due to gravity ≈ 9.8 m/s² d = distance lifted = 5 m θ = angle between the force and the direction of motion (cos(θ) = 1 for vertical lifting)

Calculate: W = 78 kg × 9.8 m/s² × 5 m W ≈ 3822 Joules

The work done to raise a 78 kg weight 5 m vertically is approximately 3822 Joules.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.