Home > Physics > Work

How much work does it take to raise a #7 kg # weight #23 m #?

Answer 1

It takes 1578 J.

The effort required to raise it there equals the gravitational potential energy gain, according to the conservation of energy principle.

The gravitational potential energy gain is expressed as follows:

#DeltaGPE = m*g*Deltah = 7 kg*9.8 m/s^2*23 m = 1578 J#

Hope this is helpful, Steve.

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer 2

#1577.8# joules

The formula yields the amount of work completed.

#W=F*d#
#F# is the force in newtons
#d# is the distance moved in meters
And so, the force is the weight of the box, which is #7 \ "kg"*9.8 \ "m/s"^2=68.6 \ "N"#.

Thus, the completed work is:

#W=68.6 \ "N"*23 \ "m"#
#=1577.8 \ "J"#
Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer 3

To calculate the work done in raising a weight against gravity, you can use the formula:

Work = Force × Distance

The force exerted when raising an object against gravity is equal to its weight, which can be calculated using the formula:

Weight = Mass × Gravity

Where:

  • Mass (m) = 7 kg (given)
  • Gravity (g) = 9.8 m/s² (approximate acceleration due to gravity on Earth)

So, Weight = 7 kg × 9.8 m/s² = 68.6 N

Now, you can calculate the work done:

Work = Force × Distance = Weight × Distance

Work = 68.6 N × 23 m = 1577.8 J

Therefore, it takes approximately 1577.8 Joules of work to raise a 7 kg weight by 23 meters against gravity.

Sign up to view the whole answer

By signing up, you agree to our Terms of Service and Privacy Policy

Sign up with email
Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

Not the question you need?

Drag image here or click to upload

Or press Ctrl + V to paste
Answer Background
HIX Tutor
Solve ANY homework problem with a smart AI
  • 98% accuracy study help
  • Covers math, physics, chemistry, biology, and more
  • Step-by-step, in-depth guides
  • Readily available 24/7