How much work does it take to raise a #6 kg # weight #72 m #?

Answer 1

#4320# Joules

To find out how much work has been done, use the formula:

Work #=# Force #×# Displacement #× cos theta color(blue)(rarr 1)#
Here in the mentioned problem, the object weighing #6kg# is raised to a height of #72 m#
Here, #6kg# is actually the mass of the object and #72kg# is the displacement.
#:. Mass = 6 kg#

and

#Displacement =72 m color(blue)(rarr 2)#
We will take acceleration due to gravity#(g)# to be #10 ms^-2#

The force formula is as follows:

Force#= Mass × g#
#:.#By plugging in values of #Mass# and #g#, we get
Force = #6×10#
Force =#60# Newtons #color(blue)( rarr 3)#
In this problem, we see that the force is also applied in the upward direction and the displacement is also in upward direction. This implies, that the angle between force and displacement is #0^。# #:. theta = 0^。 color(blue)(rarr 4)#
Plugging in the values of displacement, force and #theta# from #color(blue)(2,3,4)# respectively in #color(blue)(1)#.
Work#= 60×72× cos 0#
Work#= 4320×1#
Work#= 4320#
#:.# Work #= 4320# Joules
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Answer 2

#4233.6 \ "J"#

We make use of the work equation, which says

#W=F*d#
#F# is the force in newtons
#d# is the distance in meters

In this case, the box's weight is the force.

The equation defines weight as

#W=mg#
#m# is the mass of the object in kilograms
#g# is the gravitational acceleration, which is around #9.8 \ "m/s"^2#.

Thus, the emphasis here is,

#6 \ "kg"*9.8 \ "m/s"^2=58.8 \ "N"#

As a result, the work is

#W=58.8 \ "N"*72 \ "m"#
#=4233.6 \ "J"#
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Answer 3

The work done is 4320 joules.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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