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How much work does it take to raise a #5 kg # weight #14 m #?

Answer 1

Work is the amount of energy required to move an object using force (in this case to overcome gravity) through a distance (in this case 14 m).

The force of gravity is equal to the mass of the object times the acceleration of gravity #(g = 9.81 m/(s^2))#.

The following result will also be in SI units of energy (joules) if we utilize SI units for everything:

#w = m times g times d = 5 kg times 9.81 m/(s^2) times 14 m = 687 J#
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Answer 2

The work done to raise a 5 kg weight by 14 m is ( W = mgh ), where ( m = 5 ) kg (mass), ( g = 9.8 ) m/s² (acceleration due to gravity), and ( h = 14 ) m (height).

Substituting the values:

( W = (5 , \text{kg})(9.8 , \text{m/s}^2)(14 , \text{m}) )

( W = 686 , \text{Joules} )

So, it takes 686 Joules of work to raise a 5 kg weight by 14 m.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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