How much work does it take to raise a #23 kg # weight #5 m #?
The task at hand is
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The work done to raise a weight vertically against gravity can be calculated using the formula: ( \text{Work} = \text{Force} \times \text{Distance} \times \text{cos}(\theta) ), where ( \text{Force} ) is the force applied, ( \text{Distance} ) is the vertical distance moved, and ( \theta ) is the angle between the force and the direction of motion. In this case, since the weight is being raised vertically, the angle ( \theta ) is ( 0^\circ ) and ( \text{cos}(0^\circ) = 1 ). Thus, the work done is simply the product of the force required (equal to the weight of the object) and the distance moved vertically. So, the work done to raise a 23 kg weight 5 m vertically is ( \text{Work} = (23 , \text{kg} \times 9.8 , \text{m/s}^2) \times 5 , \text{m} ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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