How much power is produced if a voltage of #7 V# is applied to a circuit with a resistance of #42 Omega#?

Answer 1

Sebastian Acosta

The power is #=1.17W#

The authority is

#P=UI#

and Ohm's Law is

#U=RI#

#I=U/R#

Consequently,

#P=U*U/R=U^2/r#

The voltage is #U=7V#

The resistance is #R=42 Omega#

Consequently,

The authority is

#P=(7^2)/42=49/42=1.17W#

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Answer 2

William Audy

Approximately #1.17# watts.

Power in here is given by the equation:

#P=V^2/R#

where:

#P# is the power in watts

#V# is the voltage in volts

#R# is the resistance in ohms

So, we get:

#R=(7 \ "V")^2/(42 \ Omega)#

#=(49 \ "V"^2)/(42 \ Omega)#

#~~1.17 \ "W"#

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Answer 3

Julia Aguilar

The power produced in the circuit is 1 watt.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.