How much power is produced if a voltage of #3 V# is applied to a circuit with a resistance of #9 Omega#?

Answer 1

#1W#

#P = V^2/R = 3^2/9 = 1W#
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Answer 2

The power produced in the circuit is 1 watt.

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Answer 3

The power produced in the circuit can be calculated using the formula ( P = \frac{V^2}{R} ), where ( V ) is the voltage applied and ( R ) is the resistance.

Substituting the given values, ( V = 3 , \text{V} ) and ( R = 9 , \Omega ), into the formula, we get:

[ P = \frac{(3 , \text{V})^2}{9 , \Omega} ]

[ P = \frac{9 , \text{V}^2}{9 , \Omega} ]

[ P = 1 , \text{W} ]

Therefore, the power produced in the circuit is ( 1 , \text{W} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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