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How much power is needed to accelerate an object with a mass of #4 kg# and a velocity of #3 m/s# at a rate of #6 m/s^2#?

Answer 1

Olivia Askew

#P=72" Watt"#

#P=W/(Delta t)" (definition of power)"#

#W=F*Delta x" (definition of work"#

#F=m*a" (The Newton's second law of motion)"#

#W=m*a*Delta x#

#P=(m*a*Delta x)/(Delta t)#

#(Delta x)/(Delta t)=v#

#P=m*a*v" (definition of velocity)"#

#P:"Power"#

#"m:mass of object ;(4 kg)"#

#a:"acceleration of object ;(6) "m/s^2#

#v:"velocity of object ;(3) "m/s#

#P=4*6*3#

#P=72" Watt"#

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Answer 2

Adam Arnold

The power needed to accelerate an object can be calculated using the formula:

[ P = F \cdot v ]

Where ( P ) is the power, ( F ) is the force applied, and ( v ) is the velocity of the object.

The force applied to accelerate an object can be found using Newton's second law:

[ F = m \cdot a ]

Where ( m ) is the mass of the object and ( a ) is the acceleration.

Substituting the values into the equation, we get:

[ F = 4 , \text{kg} \times 6 , \text{m/s}^2 = 24 , \text{N} ]

Now, we can calculate the power:

[ P = 24 , \text{N} \times 3 , \text{m/s} = 72 , \text{W} ]

So, the power needed to accelerate the object is ( 72 , \text{W} ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.