# How much heat is added when 22 grams of water are heated from 10°C to 15°C?

And the heat capacity of water is

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The amount of heat added can be calculated using the formula:

Q = mcΔT

Where: Q = amount of heat added (in joules) m = mass of the substance (in grams) c = specific heat capacity of the substance (in J/g°C) ΔT = change in temperature (in °C)

For water, the specific heat capacity (c) is 4.18 J/g°C.

Given: m = 22 grams ΔT = 15°C - 10°C = 5°C

Plugging in the values:

Q = (22 g) * (4.18 J/g°C) * (5°C) Q = 462.2 joules

Therefore, 462.2 joules of heat are added when 22 grams of water are heated from 10°C to 15°C.

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