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How much greater is #(-14x^7 + 19x^6 - 17) " than " (5x^5 - 10x^4 + 18)#?

Answer 1

#-14x^7+19x^6-5x^5+10x^4-35#

To solve you must put the bigger expression on top and the smaller expression on the bottom and subtract. We are told the first expression is greater. #-14x^7+19x^6-17# #ul(- (5x^5-10x^4+18))#

Distribute the negative

#-14x^7+19x^6-17# #ul(- 5x^5+10x^4-18)#

Now simplify the like terms #-14x^7+19x^6 -5x^5+10x^4-35#

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Answer 2

Ethan Adkins

To find how much greater (-14x^7 + 19x^6 - 17) is than (5x^5 - 10x^4 + 18), we subtract the second polynomial from the first one:

(-14x^7 + 19x^6 - 17) - (5x^5 - 10x^4 + 18)

= -14x^7 + 19x^6 - 17 - 5x^5 + 10x^4 - 18

= -14x^7 + 19x^6 - 5x^5 + 10x^4 - 17 - 18

= -14x^7 + 19x^6 - 5x^5 + 10x^4 - 35

So, the expression (-14x^7 + 19x^6 - 17) is greater than (5x^5 - 10x^4 + 18) by the polynomial -5x^5 + 10x^4 - 35.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.