How much energy is required to melt 1.5 kg of lead?

Answer 1

#34.53#kJ

The enthalpy of fusion (energy need to change state from solid to liquid) of lead is 4.77 kJ/mol (so it takes 4.77 kJ to melt one mole of lead). We need to find the number of moles (#n#) of lead in 1.5kg (#m#).
#n=m/M# From periodic table, M=207.2g/mol Therefore, #n=(1500g)/(207.2g.mol^-1)# #n=7.24# moles Energy #=7.24#moles#*4.77kJ.mol^-1# Energy #34.53#kJ
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Answer 2

The heat of fusion for lead is 23 kJ/kg. Therefore, 34.5 kJ of energy is needed.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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