How much energy is needed to heat 1 kg of sand, which has a specific heat of 664 j/(kg k) from 30°c to 50°c?
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The energy needed to heat 1 kg of sand from 30°C to 50°C can be calculated using the formula:
[ Q = mc\Delta T ]
Where:
- ( Q ) is the energy required (in joules)
- ( m ) is the mass of the sand (1 kg)
- ( c ) is the specific heat capacity of the sand (664 J/(kg·K))
- ( \Delta T ) is the change in temperature (50°C - 30°C = 20°C)
Substituting the values into the formula:
[ Q = (1 kg) \times (664 J/(kg·K)) \times (20°C) ]
[ Q = 13280 J ]
So, the energy needed to heat 1 kg of sand from 30°C to 50°C is 13280 joules.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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