How much carbon can be obtained from 65.3 g of #Ca(C_2H_3O_2)_2#?

Answer 1

Approximately #19.8# grams

Approximate the molar mass of the constituent elements as follows:

#Ca: 40# g/mol
#C: 12# g/mol
#H: 1# g/mol
#O: 16# g/mol
Then the mass of #Ca(C_2H_3O_2)_2# is:
#40+2((2*12)+(3*1)+2*(16))#
#=40+2(24+3+32)#
#=40+2*59#
#=158# g/mol
of which #4*12 = 48# g/mol is carbon.
So in #65.3"g"# of #Ca(C_2H_3O_2)_2#, the mass of carbon is:
#65.3*48/158 ~~ 19.8"g"#
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Answer 2

The mass of carbon obtained is approximately 4.95 g. The molar mass of Ca(C₂H₼O₂)₂ is approximately 158.17 g/mol. This means that 65.3 g of Ca(C₂H₃O₂)₂ contains about 0.413 moles of the compound. Since each mole contains one mole of carbon, the amount of carbon is also 0.413 moles.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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