# How much alcohol is in a 9-oz solution of water and alcohol that is 20% alcohol?

The amount of alcohol is 1.8 oz.

Eighty percent is water in an alcohol solution with twenty percent alcohol.

20% of the volume, or 0.20 x 9 = 1.8 oz, is alcohol if the total volume is 9 ounces.

To make this solution, 1.8 ounces of alcohol and 7.2 ounces of water were combined.

To summarize, 20% of alcohol is equivalent to 1.8 ounces, and 80% is equivalent to 7.2 ounces.

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To calculate the amount of alcohol in a 9-oz solution that is 20% alcohol, you first find 20% of 9 oz, then convert that to ounces.

[ \text{Amount of alcohol} = \text{Total volume} \times \text{Alcohol percentage} ]

[ \text{Amount of alcohol} = 9 \text{ oz} \times 0.20 ]

[ \text{Amount of alcohol} = 1.8 \text{ oz} ]

So, there are 1.8 ounces of alcohol in a 9-ounce solution that is 20% alcohol.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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