How many turns of wire must a coil have in order to induce a voltage of 10.5 volts when exposed to a changing magnetic flux with a rate of 0.0075 Wb/s?

Answer 1
The Faraday's law of electromagnetic induction (incorporating Len's law) gives the induced emf for a coil with #N# number of turns as: #\xi_{"i"nd}=-N(d\Phi_B)/(dt) \qquad => \qquad | \xi_{"i"nd} | = N |(d\Phi_B)/(dt)|#.
#| \xi_{"i"nd} | = 10.5 V; \qquad (d\Phi_B)/(dt) = 7.5\times10^{-3} Wb.s^{-1}; \qquad N=?#
#N = (|\xi_{"i"nd}|)/(|(d\Phi_B)/(dt)|) = (10.5 V)/(7.5\times10^{-3}Wb.s^{-1})=1400# turns.
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Answer 2

Number of turns (N) = Voltage (V) / (Change in magnetic flux per second (ΔΦ/t)) N = 10.5 volts / 0.0075 Wb/s N = 1400 turns

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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