How many stereoisomers are possible for CHBrClF provided that the central carbon has a square planar geometry?

Answer 1

There are three possible stereoisomers for a square planar #"CHBrClF"#.

They are

Start with #"H"# and #"Br"# cis to each other.

Then you can put #"F"# or #"Cl"# trans to the #"H"#. This gives you two of the isomers.

For the third isomer, put #"H"# and #"Br"# trans to each other.

There are no optical isomers for square planar #"CHBrClF"#, because any planar compound has a mirror plane in the plane of the paper, dividing the top half of each atom into a mirror image of its bottom half.

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Answer 2

For CHBrClF with a square planar geometry, there are two possible stereoisomers: cis and trans.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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