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How many solutions does the equation # 6x^2 -2x = -9# have?

Answer 1

No real solutions

If we look at the formula for solving a quadratic #x =(-b+-sqrt(b^2-4ac))/(2a)# we can see the determinant. #b^2-4ac#

This is the bit that determines whether the equation has 2 real roots, 1 root or no real roots If the determinant is greater than zero there are 2 real roots, if it is zero there is one solution ( the graph of the equation touches the x axis) In this case #b^2-4ac#=#(-2)^2-4*6*9#=-212 There is no real number which is #sqrt(-216)#

The graph of this equation does not cross the x axis

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Answer 2

Genesis Allen

The equation 6x^2 - 2x = -9 has two solutions.

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Answer 3

Eli Assouline

The equation 6x^2 - 2x = -9 has two solutions.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.