How many representative particles are in 6.8 g of #H_2O#?

Answer 1

#"Number of particles"# #-=# #"Mass"/"Molar mass"xxN_A#, where #N_A="Avogadro's number", 6.022xx10^23#.

I KNOW that an #18.01*g# mass of water contains #"Avogadro's number of molecules"#, i.e. #6.022xx10^23# INDIVIDUAL WATER molecules.

And thus the number of water molecules, i.e. representative particles, in a #6.8*g# mass is:

#(6.8*g)/(18.01*g*mol^-1)xx6.022xx10^23*mol^-1-="How many water molecules"#.

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Answer 2

Axel Alvarado

To find the number of representative particles in 6.8 g of H2O, you first need to calculate the number of moles of H2O using its molar mass. The molar mass of H2O is approximately 18.015 g/mol. Then, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) particles/mol, to convert moles to representative particles.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.