How many mols #CaCO_3# can be dissolved in .0250 mol #HCl# in the equation #CaCO_3 + 2HCl -> CaCl_2 + H_2O + CO_2#?

Answer 1

#0.0125molCaCO_3#

The formula states

#CaCO_3 + 2HCl#,
which means that for every #2# moles of #HCl# there is one of #CaCO_3#. This is called the molar ratio, in this case #2:1#.
We know that there are #0.0250# moles of #HCl#, which is equal to two parts in the ratio. If #0.0250# is two parts, then one part must be #0.0125#.
And, since there is only one part of #CaCO_3# in the ratio, then you can dissolve #0.0125# moles of #CaCO_3# in #0.0250# moles of #HCl#.
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Answer 2

By examining the balanced chemical equation, we can see that 1 mole of CaCO₃ reacts with 2 moles of HCl. Thus, if there are 0.0250 moles of HCl available, the number of moles of CaCO₃ that can be dissolved is half of that, which is 0.0125 moles.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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