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How many moles of #ZnCl# are in 100 mL of 0.300 M solution?

Answer 1

Wyatt Adkins

There are 0.030 mol of #ZnCl#

Let's get started by using the equation below:

Now, we identify our knowns and unknowns:

#color(purple)("Knowns:")#

Volume
Molarity
#color(blue)("Unknown:")#
- Moles of Solute
  We are given the molarity and the volume of solution. The only issue is that the volume is given in mL instead of L. This issue can be fixed by using the following conversion factor:
  
  #color(white)(aaaaaaaaaaaaaaaaaaaaa)1000mL = 1L#
  Therefore, if we divide 100mL by 1000mL we will obtain a value of 0.100L.
  
  Next, the equation has to be rearranged to solve for the moles of solute:
  
  #color(red)("Moles of solute = Molarity x Liters of solution"#
  Now, multiply 0.300 M by 0.100 L
  
  #(0.300 mol)/cancelL xx0.100cancelL = "0.030 mol"#
  Thus, there are 0.030 mol of #ZnCl#

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Answer 2

Avery Adams

There are 0.0300 moles of ZnCl in 100 mL of 0.300 M solution.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.