# How many moles of #PCL_5# can be produced from 22.0 g of #P_4# (and excess #Cl_2)#?

Approx.

To depict the reaction, we require (i) a stoichiometric equation:

Integral numbers can be obtained by multiplying the coefficients out if desired:

If you use the earlier equation, I think handling the multiplication will be a little simpler.

Additionally, we require (ii) equal amounts of every reactant:

There is an abundance of the gas oxidant chlorine.

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From 22.0 g of P3 (and excess Cl3₂), 5.5 moles of PCl₅ can be made.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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