How many moles of P4 are needed to react with 9 moles of Mg? 6 Mg + P4 → 2 Mg3P2

Answer 1

Let's examine the equation:

6Mg + #P_4# .............>2 #Mg_3# #P_2#

according to this equation 1 mole of #P_4# reacts with 6 moles of Mg. So my recipe is 1 mole of #P_4# is required for every 6 moles of Mg.

1 mole of #P_4# / 6 moles of Mg ......(a)

X moles of #P_4# completely reacts with 9 moles of Mg

X moles of #P_4# / 9 moles of Mg ......(b)

Both ratios are the same.

(a) equals (b)

1 mole of #P_4# / 6 moles of Mg = X moles of #P_4# / 9 moles of Mg

6 times X equals 9.

X = 3/2 = 1.5 mole, or 9/6.

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Answer 2

Jose Ayala

To balance the chemical equation, we see that 6 moles of magnesium (Mg) react with 1 mole of phosphorus (P4) to produce 2 moles of magnesium phosphide (Mg3P2).

So, if 6 moles of Mg react with 1 mole of P4, then 9 moles of Mg will react with:

(9 moles Mg) / (6 moles Mg/1 mole P4) = 1.5 moles P4.

Therefore, 1.5 moles of P4 are needed to react with 9 moles of Mg.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.