# How many moles of oxygen are present in 33.6 L of the gas at 1 atm and 0°C?

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To find the number of moles of oxygen, we can use the ideal gas law equation:

n = (PV) / (RT)

Where: P = pressure (in atm) V = volume (in liters) n = number of moles R = ideal gas constant (0.0821 L.atm/mol.K) T = temperature (in Kelvin)

Given: P = 1 atm V = 33.6 L R = 0.0821 L.atm/mol.K T = 0°C + 273.15 = 273.15 K

Substituting the values into the equation:

n = (1 atm * 33.6 L) / (0.0821 L.atm/mol.K * 273.15 K) n ≈ 1.325 moles

Therefore, there are approximately 1.325 moles of oxygen present in 33.6 L of the gas at 1 atm and 0°C.

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