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How many moles of #N# are in 0.193 g of #N_2O#?

Answer 1

Caleb Adams

There are #=8.77xx10^-3*mol" of nitrogen atoms.........."#

#"Moles of nitrous oxide"# #=# #(0.193*g)/(44.01*g*mol^-1)#

#=4.39xx10^-3*mol.#

And thus #"moles of nitrogen atoms"#

#=4.39xx10^-3*molxx2=??#

How can I get the number of nitrogen atoms from this molar quantity?

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Answer 2

Mateo Aguilar

Determine the moles of N as follows: [ \text{Moles of N} = \frac{\text{Mass of N}}{\text{Molar mass of N}} ] [ \text{Molar mass of N} = 14.01 , \text{g/mol} ] [ \text{Moles of N} = \frac{0.193 , \text{g}}{14.01 , \text{g/mol}} ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.