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How many moles of #N_2# are formed by the decomposition of 2.5 moles of #NaN_3#?

Answer 1

Owen Ambrose

#5.8 mols#

first multiply the mols with the mr #65*2.5=162.5# then use this to get the mols of #N_2# #mols=162.5/28# #mols=5.8#

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Answer 2

Olivia Anton

#3.75molN_2#

The decomposition reaction of sodium azide #NaN_3# is:

#2NaN_3(s)->2Na(s)+3N_2(g)#

Using dimensional analysis, we can find the number of mole of #N_2# gas formed:

#?molN_2(g)=2.5cancel(mol NaN_3)xx(3molN_2)/(2cancel(molNaN_3))=3.75molN_2#

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Answer 3

Henry Antrim

The balanced equation for the breakdown of NaN3 is as follows: 2 NaN3 → 3 N2 + 2 Na. Based on this equation, it is clear that every 2 moles of NaN3 that decompose, 3 moles of N2 are produced. Consequently, if 2.5 moles of NaN3 break down, the amount of N2 that is produced can be computed using the following formula: 2.5 moles NaN3 * (3 moles N2 / 2 moles NaN3) = 3.75 moles N2. This means that the breakdown of 2.5 moles of NaN3 results in 3.75 moles of N2.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.