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How many moles of ions are in 27.5 g of #MgCl_2#?

Answer 1

Jeremiah Adams

#MgCl_2(s) rarr Mg^(2+) +2Cl^-#

#"Moles of magnesium salt"# #=# #(27.5*g)/(95.21*g*mol^-1)# #=# #0.289*mol.#

There are thus #2xx0.289*mol# #"chloride ions"#, and #0.289*mol# #"magnesium ions"#, almost an entire mole of ions.

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Answer 2

Cooper Adams

Calculate moles of MgCl₂, then multiply by Avogadro's number.

Find molar mass of MgCl₂: 95.211 g/mol
Moles of MgCl₂ = 27.5 g / 95.211 g/mol
Moles of ions (Cl⁻) = 2 × moles of MgCl₂
Multiply moles of ions by Avogadro's number (6.022 × 10²³ mol⁻¹).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.