How many moles of hydrogen will be needed to react with 2 moles of nitrogen in the reaction #N_2 + H_2 -> NH_3#?

Answer 1

The balanced equation for dinitrogen reduction is:
#N_2(g) + 3H_2(g) rarr 2NH_3(g)#.

#2# #"moles"# #N_2# requires #6# moles #H_2#.

Due to its ability to produce ammonia and nitrates for the production of nitrogenous fertilizer, the equation above likely represents the most significant inorganic reaction on the planet.

Your question specified 2 moles of nitrogen. I would be quite justified in assuming that the questioner meant 2 moles of dinitrogen gas, i.e. the equivalent of #4# moles of #"NITROGEN"# atoms.

Thus, if #2# moles of dinitrogen gas are specified, #6# moles of dihydrogen gas are required.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Kai Bowman

One mole of nitrogen reacts with three moles of hydrogen to produce two moles of ammonia. Therefore, to react with 2 moles of nitrogen, you would need 6 moles of hydrogen.

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How many moles of hydrogen will be needed to react with 2 moles of nitrogen in the reaction #N_2 + H_2 -&gt; NH_3#?

How many moles of hydrogen will be needed to react with 2 moles of nitrogen in the reaction #N_2 + H_2 -> NH_3#?