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How many moles of #H_2SO_4# are required to completely neutralize 0.10 moles of #Ca(OH)_2#?

Answer 1

0.10 moles or 9.8 grams.

Two molecules of water and CaSO4 are produced when the reaction takes place.

It indicates that one mole of Ca(OH)2 reacts for every mole of sulfuric acid.

Sulphuric acid (0.1 mol) is required for every 0.1 mol of Ca(OH)2. Alternatively, 9.8 grams (or 0.1 mol) of H2SO4 are required for every 7.4 grams of Ca(OH)2.

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Answer 2

Cameron Andrews

0.20 moles of H₂SO₄ are required to completely neutralize 0.10 moles of Ca(OH)₂.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.