# How many moles of gas occupy 22.4 liters at 27 Celsius degrees and 0.50 atm of pressure?

Thanks for the gas law question.

In order to solve this problem, we can use the Ideal Gas Law.

PV = nRT

Pressure needs to be in atmospheres (.50 atm)

Volume needs to be in liters (22.4 L)

n is the number of moles (and your unknown in this particular question)

R is the universal gas constant (R = .08206

T is the temperature in K (oC + 273 = K, so 27oC + 273 = 300. K)

(.50 atm) ( 22.4 L) = n (.08206

Please do the math and check your answer below:

The number of moles (n) is .45 moles. This number is rounded to the correct number of significant figures.

Have fun with the gas calculations!!

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To find the number of moles of gas occupying (22.4 , \text{liters}) at (27 , \text{degrees Celsius}) and (0.50 , \text{atm}) of pressure, we can use the ideal gas law equation:

[PV = nRT]

Where:

- (P) is the pressure in atm
- (V) is the volume in liters
- (n) is the number of moles
- (R) is the ideal gas constant ((0.0821 , \text{atm} \cdot \text{L} / \text{mol} \cdot \text{K}))
- (T) is the temperature in Kelvin

First, we need to convert the temperature to Kelvin: (27 + 273 = 300 , \text{K}).

Now we can rearrange the equation to solve for (n):

[n = \frac{PV}{RT}]

Substituting the given values:

[n = \frac{(0.50 , \text{atm})(22.4 , \text{L})}{(0.0821 , \text{atm} \cdot \text{L} / \text{mol} \cdot \text{K})(300 , \text{K})}]

[n ≈ \frac{11.2}{24.63}]

[n ≈ 0.454 , \text{moles}]

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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