How many moles of copper are equivalent to #3.44*10^23# atoms of copper?

Answer 1

#0.571 " mol."#

Finding the conversion factor is the first step. Since we know that one mol contains Avogadro's number of atoms, our conversion factor is:

# \ 1 " mol." = 6.02xx10^23 " atoms"#
#3.44xx10^23 \ "atoms" xx (1 \ "mol.")/(6.02xx10^23 \ "atoms")#
#3.44xx10^23\ cancel("atoms") xx (1 \ "mol.")/(6.02xx10^23 \ cancel("atoms"))#
#0.571 " mol."#
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Answer 2

Divide the given number of atoms by Avogadro's number, which is (6.022 \times 10^{23}) atoms/mol, to find the number of moles of copper equivalent to (3.44 \times 10^{23}) atoms of copper. As a result, (3.44 \times 10^{23}) atoms of copper is equivalent to roughly (0.571) moles of copper.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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