How many moles are in sodium chloride in 150 mL of a 2 mM NaCl solution?

Question

Olivia Anton · Accepted Answer

#"Concentration"="Moles of solute"/"Volume of solution"#. And here there are:
#150xx10^-3cancelLxx2xx10^-3*mol*cancel(L^-1)=3.00xx10^-4*mol# of solute.

#"Concentration"="Moles of solute"/"Volume of solution"#

And thus #"moles of solute"="volume"xx"concentration"#

And for this item, we have the following:

#150xx10^-3cancelLxx2xx10^-3*mol*cancel(L^-1)=3.00xx10^-4*mol#.

(I have changed the volume from #mL# to #L#, and from #mmol# to #mol# simply by using the appropriate multiplier.

Natalie Anton · Answer

undefined To calculate the number of moles of sodium chloride in the solution, you first need to convert the volume from milliliters to liters (since the concentration is given in millimoles per liter). Then, you can use the formula:

$$ \text{moles} = \text{concentration} \times \text{volume} $$

$$ \text{moles} = 2 \times 10^{-3} \, \text{mol/L} \times 0.150 \, \text{L} $$

$$ \text{moles} = 3 \times 10^{-4} \, \text{mol} $$

So, there are $3 \times 10^{-4}$ moles of sodium chloride in 150 mL of a 2 mM NaCl solution.