How many molecules of carbon dioxide will be produced if 20 molecules of propane react?
To depict the combustion, you need an equation that is stoichiometrically balanced:
Therefore, are mass and charge balanced here?
The reaction clearly calls for 3 equivalents of carbon dioxide to every equivalent of propane, so if we begin with 20 molecules of propane, there will unavoidably be 60 molecules of carbon dioxide product after the propane is completely burned.
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The balanced chemical equation for propane combustion (C₃H₈) is as follows: C₃H₈ + 5O₂ → 3CO₂ + 4H₂O. This means that for every 20 propane molecules that react, 3 molecules of carbon dioxide are produced; therefore, for every 20 propane molecules, 60 molecules of carbon dioxide will be produced.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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