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How many mL of NaOH are needed to neutralize the acidity in a titrated solution containing .1234 g of #AlCl_3#?

Answer 1

you must know the molarity of NaOH solution!

for #AlCl_3# #N° mol = G/(MM) =(0,1234g)/ (133,35g/(mol)) = 9,25 10^(-4) mol = 0,925 mmol# for NaOH n= M V n° mol = Molarity x Volume #V=( N°mol)/ (Molarity)= (0,925 mol)/(x M) = y mL#

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Answer 2

Cooper Anderson

38.13 mL.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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