How many mL of a 0.124 moles/L solution of potassium permanganate contain 0.722 g of the salt?
As you are aware, molarity is the quantity of solute in moles per liter of a particular solution.
To solve this problem, one interesting approach would be to change the solution's molarity from moles per liter to grams per milliliter.
Additionally, you are aware that you have
which indicates that the solution's molarity corresponds to a concentration of
Three sig figs are used to round the result.
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To find the volume of the solution, we first need to calculate the number of moles of potassium permanganate (KMnO4) in 0.722 g using its molar mass. Then, we can use the molarity of the solution to find the volume.

Calculate the number of moles of KMnO4: ( \text{Molar mass of KMnO}_4 = 158.034 , \text{g/mol} ) ( \text{Number of moles} = \frac{0.722 , \text{g}}{158.034 , \text{g/mol}} )

Use the formula for molarity: ( \text{Molarity} = \frac{\text{Number of moles}}{\text{Volume (in liters)}} ) We rearrange the formula to find the volume: ( \text{Volume (in liters)} = \frac{\text{Number of moles}}{\text{Molarity}} )

Convert the volume from liters to milliliters.
Performing the calculations:

( \text{Number of moles} = \frac{0.722 , \text{g}}{158.034 , \text{g/mol}} \approx 0.00457 , \text{moles} )

( \text{Volume (in liters)} = \frac{0.00457 , \text{moles}}{0.124 , \text{moles/L}} \approx 0.0369 , \text{L} )

( \text{Volume (in milliliters)} = 0.0369 , \text{L} \times 1000 = 36.9 , \text{mL} )
Therefore, 36.9 mL of the 0.124 moles/L solution of potassium permanganate contain 0.722 g of the salt.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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