How many milliliters of 0.75 M solution can be made using 75 grams of lead (II) oxide (#PbO#)?

Question

Wyatt Atkins · Accepted Answer

It can't be done.

The solubility of #"PbO"# is only about #8 × 10^"-5"color(white)(l) "mol/L"#.

Ellie Andrews · Answer

undefined To find the volume of the solution, we first need to calculate the number of moles of lead (II) oxide (PbO) using its molar mass. Then, we can use the given molarity to find the volume of the solution.

1. Calculate the molar mass of PbO:  
   Pb: 207.2 g/mol  
   O: 16.00 g/mol  
   Molar mass of PbO = 207.2 + 16.00 = 223.2 g/mol

2. Calculate the number of moles of PbO:
   Number of moles = Mass / Molar mass
   Number of moles = 75 g / 223.2 g/mol

3. Now, use the molarity formula to find the volume of the solution:
   Molarity = Moles / Volume (in liters)
   Volume (in liters) = Moles / Molarity

4. Convert the volume from liters to milliliters:
   1 liter = 1000 milliliters

$$ \text{Number of moles} = \frac{75 \text{ g}}{223.2 \text{ g/mol}} $$

$$ \text{Volume (in liters)} = \frac{75 \text{ g}}{223.2 \text{ g/mol} \times 0.75 \text{ mol/L}} $$

$$ \text{Volume (in milliliters)} = \text{Volume (in liters)} \times 1000 $$

$$ \text{Volume (in milliliters)} = \left(\frac{75 \text{ g}}{223.2 \text{ g/mol} \times 0.75 \text{ mol/L}}\right) \times 1000 $$