How many milliliters of 0.200M #NaOH# solution are needed to react with 22.0 mL of a 0.490 M #NiCl_2# solution?

Answer 1

There are #0.0108# #mol# #NiCl_2#. #0.0216# #mol# #NaOH# are required, given #0.200# #mol*L^-1# #NaOH(aq)#.

#NiCl_2(aq) + 2NaOH(aq) rarr Ni(OH)_2(s)darr + 2NaCl(aq)#
There are #0.0108# #mol# #NiCl_2# (#22.0xx10^(-3)cancelLxx0.490*mol*cancel(L^-1)#). So, by stoichiometry #0.0216# #mol# #NaOH# are required.
There is #0.200# #mol*L^-1# #NaOH# solution available, so...
#(0.0216*cancel(mol))/(0.200*cancel(mol)*cancel(L^-1))xx1000*mL*cancel(L^-1)# #=# #?? mL#
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Answer 2

To find the volume of the NaOH solution needed to react with the NiCl2 solution, we can use the stoichiometry of the reaction. The balanced chemical equation for the reaction between NaOH and NiCl2 is:

2NaOH + NiCl2 → Ni(OH)2 + 2NaCl

From the equation, we can see that 2 moles of NaOH react with 1 mole of NiCl2. Therefore, we can use the formula:

( \text{Volume}{\text{NaOH}} \times \text{Molarity}{\text{NaOH}} \times \frac{2}{1} = \text{Volume}_{\text{NiCl}2} \times \text{Molarity}{\text{NiCl}_2} \times \frac{1}{1} )

Plugging in the given values:

( \text{Volume}_{\text{NaOH}} \times 0.200 , \text{M} \times \frac{2}{1} = 22.0 , \text{mL} \times 0.490 , \text{M} \times \frac{1}{1} )

Solving for ( \text{Volume}_{\text{NaOH}} ):

( \text{Volume}_{\text{NaOH}} = \frac{22.0 , \text{mL} \times 0.490 , \text{M}}{0.200 , \text{M} \times 2} )

( \text{Volume}_{\text{NaOH}} = 54.45 , \text{mL} )

So, 54.45 milliliters of the 0.200 M NaOH solution are needed to react with 22.0 mL of the 0.490 M NiCl2 solution.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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