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How many kilograms of solvent are there in a sample of 0.30 molal solution if the sample contains 13 moles of solute?

Answer 1

Wyatt Adkins

#43" Kg of solvent"#

The molality (#m#) is defined as: #m=n/("Kg of solvent")#,

where, #n# is the number of mole of solute.

Therefore, #"Kg of solvent"=n/m=(13cancel(mol))/(0.30cancel(mol)/(Kg))=43" Kg of solvent"#

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Answer 2

Cooper Anderson

To find the mass of the solvent, you can use the formula:

Mass of solvent = Moles of solute / Molality

Given that the molality (m) is 0.30 mol/kg and the moles of solute (n) is 13 moles:

Mass of solvent = 13 moles / 0.30 mol/kg

Mass of solvent = 43.33 kg

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.