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How many joules of heat would be required to heat 0.5 kg of aluminum by 2K?

Answer 1

Ellie Andrews

#902# #J#

Use the equation #Q=mcdeltaT#

Where #Q=#heat flow, #m=#mass, #c=#specifc heat capacity of #Al# and #deltaT=#change in temperature

Just looking up the specific heat capcity of aluminum off google, which is #0.902# #J/(g*C)#

Sub values in with their correct units (the change in the kelvin scale is the same in celsius)

#Q=(500g)*0.902(J/(g*C))*(2# celsius)

#Q=902# #J#

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Answer 2

Axel Alvarado

To calculate the heat required, you can use the specific heat capacity of aluminum, which is 0.9 J/g°C. First, convert the mass of aluminum from kg to g:

0.5 kg * 1000 g/kg = 500 g

Now, use the formula:

Q = mcΔT

Where: Q = heat energy (in joules) m = mass (in grams) c = specific heat capacity (in J/g°C) ΔT = change in temperature (in °C)

Plugging in the values:

Q = (500 g) * (0.9 J/g°C) * (2°C) Q = 900 J

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.