# How many joules of heat energy would be required to raise the temperature of 150.0 g of aluminum from 23°C to 150°C?

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The specific heat capacity of aluminum is .90 #J# #/g*°C# .

The specific heat capacity of aluminum is .90

Your tool of choice here will be the following equation

In your case, the change in temperature will be

Rounded to two sig figs, the answer will be

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To calculate the heat energy required to raise the temperature of a substance, you can use the formula:

Q = mcΔT

Where:

- Q is the heat energy (in joules),
- m is the mass of the substance (in grams),
- c is the specific heat capacity of the substance (in joules per gram per degree Celsius),
- ΔT is the change in temperature (in degrees Celsius).

For aluminum, the specific heat capacity is approximately 0.897 J/g°C.

Given:

- Mass (m) = 150.0 g
- Initial temperature (T1) = 23°C
- Final temperature (T2) = 150°C

Calculate ΔT: ΔT = T2 - T1 ΔT = 150°C - 23°C ΔT = 127°C

Now, plug the values into the formula: Q = (150.0 g) * (0.897 J/g°C) * (127°C)

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