How many joules are required for heating 65 g of water from 12 °C to 76 °C?
With knowledge of the specific heat capacity of a substance, its mass, and the temperature change, we can convert this to the energy required for this temperature change using:
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To calculate the energy required to heat water, you can use the formula:
Q = mcΔT
Where: Q = heat energy (in joules) m = mass of water (in grams) c = specific heat capacity of water (4.18 J/g°C) ΔT = change in temperature (final temperature - initial temperature)
Substitute the given values into the formula:
m = 65 g c = 4.18 J/g°C ΔT = (76°C - 12°C) = 64°C
Q = (65 g) * (4.18 J/g°C) * (64°C) Q ≈ 17192 joules
So, approximately 17192 joules of energy are required to heat 65 g of water from 12°C to 76°C.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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