How many joules are required for heating 65 g of water from 12 °C to 76 °C?

Answer 1

#17000# joules

With knowledge of the specific heat capacity of a substance, its mass, and the temperature change, we can convert this to the energy required for this temperature change using:

#DeltaH=mCDeltaT#, where
#DeltaH=#change in enthalpy (J)
#m=# mass of substance being heated (g) i.e. water in this question
#C=# specific heat capacity (J/g°C)
#DeltaT=# change in temperature (°C)
We know mass#=65g# and #DeltaT=76°C-12°C=64°C#
The specific heat capacity of water is #4.18#J/g°C
Therefore, #DeltaH=65cancel(g)*(4.18J)/cancel(g°C)*64cancel(°C)#
#=17388.8J#
#=17000J# (2 significant figures)
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Answer 2

To calculate the energy required to heat water, you can use the formula:

Q = mcΔT

Where: Q = heat energy (in joules) m = mass of water (in grams) c = specific heat capacity of water (4.18 J/g°C) ΔT = change in temperature (final temperature - initial temperature)

Substitute the given values into the formula:

m = 65 g c = 4.18 J/g°C ΔT = (76°C - 12°C) = 64°C

Q = (65 g) * (4.18 J/g°C) * (64°C) Q ≈ 17192 joules

So, approximately 17192 joules of energy are required to heat 65 g of water from 12°C to 76°C.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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