How many joules are needed to boil 59.8 g of ethanol if the heat of vaporization is 854 J/g?

Answer 1

51,069.2 J

Use the heat of vaporization formula: #q = m * H_v#

The answer to the question is 854 J/g, or 854 joules of energy required to vaporize one gram of ethanol. This is the heat of vaporization of ethanol.

We have 59.8 grams of ethanol, so enter 59.8 in the calculator and multiply the result by 854.

#q = (59.8)(854)# #q = 51069.2 # J

That is your response!

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Answer 2

Jose Ayala

The energy required to boil 59.8 g of ethanol is approximately 51,023.2 joules.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.