# How many grams of solid BaSO4 will form when Na2SO4 reacts with 25 mL of 0.50 M Ba(NO3)2? __ Ba(NO3)2 + __ Na2SO4 __ BaSO4 + __ NaNO3

Initially focusing on the chemical equation in balance

By signing up, you agree to our Terms of Service and Privacy Policy

The balanced chemical equation for the reaction is:

Ba(NO3)2 + Na2SO4 → BaSO4 + 2 NaNO3

From the equation, we see that 1 mole of Ba(NO3)2 reacts with 1 mole of Na2SO4 to produce 1 mole of BaSO4.

To find the number of moles of Ba(NO3)2 reacting, we use the formula:

moles = concentration × volume (in liters)

Given that the volume of Ba(NO3)2 is 25 mL (which is 0.025 L) and the concentration is 0.50 M, we can calculate the number of moles of Ba(NO3)2:

moles of Ba(NO3)2 = 0.50 M × 0.025 L = 0.0125 moles

Since the stoichiometric coefficient of Ba(NO3)2 is 1 in the balanced equation, it reacts with 1 mole of Na2SO4.

Therefore, the number of moles of BaSO4 formed is also 0.0125 moles.

Now, to find the mass of BaSO4 formed, we use its molar mass, which is approximately 233.39 g/mol.

mass of BaSO4 = moles × molar mass = 0.0125 moles × 233.39 g/mol ≈ 2.92 grams

So, approximately 2.92 grams of solid BaSO4 will form.

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- What sort of solution will result if one equiv of hydrochloric acid is added to one equiv of calcium hydroxide? And how does #pH# relate to #pOH# in such solutions?
- What volume must the final solution reach if you want to make a #"0.01 N"# oxalic acid solution in water using #"126 g"# of oxalic acid solid?
- A buffer solution contains 0.20 M #CH_3COOH# and 0.30 M #CH_3COONa# at #25^oC#? (#Ka=1.8 x10^-5#). What is the pH after the addition of (a) 20.0 mL of 0.050 M #NaOH# or (b) 20.0 mL of 0.050 M #HCl# to 80.0 mL of this buffer solution?
- What volume of 2.50 M #"HCl"# in liters is needed to react completely (with nothing left over) with 0.750 L of 0.100 M #"Na"_2"CO"_3#?
- If 0.900 g of oxalic acid, #H_2C_2O_4# (90.04 g/mol) is completely neutralized with 0.500 M #LiOH#, what volume of lithium hydroxide is required?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7