How many grams of potassium sulfite are required to dissolve in 872g of water to make a 0.128m solution?
Now, molality is used to express the concentration of a solution in terms of how many moles of solute it contains per kilogram of solvent.
This means that in order to find a solution's molality, you need to know
In your case, you already know the mass of the solvent in grams, so the very first thing to do here is convert it to kilograms
All you have to do now is use the molar mass of potassium sulfite to figure out how many grams would contain that many moles
The answer is rounded to three sig figs.
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To make a 0.128 M solution, you would need 6.05 grams of potassium sulfite to dissolve in 872 grams of water.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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