How many grams of #O_2# are in 5.0 mol of the element?

Question

Wyatt Adkins · Accepted Answer

Assume that: M = molar mass (g/mol) n = number of moles (mol) m = mass of substance (g)

In #O_2#, the number of moles (n) has been provided for you = 5 moles.

In order to find the mass (m) of #O_2#, you first have to find the molar mass (M) of #O_2#.

Use this formula to help you: #n = m -: M#.

You know that #O_2# is composed of 2 atoms of Oxygen.

According to your periodic table, oxygen has an atomic weight of 16.0 g/mol, or its molar mass.

Since there are 2 atoms in #O_2#, you have to multiply the number of atoms provided by the molar mass of each atom. Which is 2 #xx# 16.0 g/mol therefore it will give you 32.0 g/mol as the molar mass (M).

Your final step is to find the mass (m) of #O_2#.

Refer back to this formula to help you: #n = m -: M#. Now you have to make #m# as the subject (I'm not sure whether have you learned making an alphabet as a subject in Algebra).

To make #m# as the subject, send #M# to the left hand side therefore it will be multiplied by #n#. Now your formula should look like : #n xx M = m#.

Therefore, 5 moles #xx# 32.0 g/mol = 160 grams is the mass (m) when there are 5 moles of #O_2#.

(I apologize if my explanation is too detailed; I'm doing my best to make sure you understand.)

Caleb Adams · Answer

undefined About 80 grams of oxygen (O₂) make up 5.0 moles of the element.