# How many grams of NaCl are contained in 350. mL of a 0.287 M olution of sodium chloride?

Approx.

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To calculate the grams of NaCl, use the formula:

[ \text{Mass (g)} = \text{Volume (L)} \times \text{Concentration (M)} \times \text{Molar mass (g/mol)} ]

[ \text{Molar mass of NaCl} = 22.99 , \text{g/mol (Na)} + 35.45 , \text{g/mol (Cl)} = 58.44 , \text{g/mol} ]

[ \text{Mass (g)} = 0.350 , \text{L} \times 0.287 , \text{M} \times 58.44 , \text{g/mol} ]

[ \text{Mass (g)} = 6.9974 , \text{g} ]

So, there are approximately 7.00 grams of NaCl in 350 mL of a 0.287 M solution of sodium chloride.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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