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How many grams of NaCl are contained in 350. mL of a 0.287 M olution of sodium chloride?

Answer 1

Naomi Aronson

Approx. #6*g# of salt.

#"Concentration"# #=# #"Moles of solute"/"Volume of solution"#

And thus, #"moles of solute"="concentration"xx"volume of solution"#.

So, #"moles"# #=# #350xx10^-3*Lxx0.287*mol*L^-1=0.100*mol#.

And #"mass of salt"# #=# #0.100*molxx58.44*g*mol=??g#

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Answer 2

Mateo Aguilar

To calculate the grams of NaCl, use the formula:

[ \text{Mass (g)} = \text{Volume (L)} \times \text{Concentration (M)} \times \text{Molar mass (g/mol)} ]

[ \text{Molar mass of NaCl} = 22.99 , \text{g/mol (Na)} + 35.45 , \text{g/mol (Cl)} = 58.44 , \text{g/mol} ]

[ \text{Mass (g)} = 0.350 , \text{L} \times 0.287 , \text{M} \times 58.44 , \text{g/mol} ]

[ \text{Mass (g)} = 6.9974 , \text{g} ]

So, there are approximately 7.00 grams of NaCl in 350 mL of a 0.287 M solution of sodium chloride.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.